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PLEASE HELP WITH WHERE TO DOT!!!

At an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth. Sixteen seconds pass from the time the buoy is at its highest point to when it is at its lowest point. Assume at x = 0 the buoy is at normal ocean depth.

Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

PLEASE HELP WITH WHERE TO DOT!!! At an ocean depth of 8 meters, a buoy bobs up and-example-1

2 Answers

7 votes

Answer:

points go at -3 on the line and at 9 one above the line

Explanation:

User Wewo
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5.6k points
3 votes

Answer with explanation:

It is given that:

At an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth.

Sixteen seconds pass from the time the buoy is at its highest point to when it is at its lowest point.

Assume at x = 0 the buoy is at normal ocean depth.

this means that when x=0 the value on the y-axis is -8.

Also, the buoy bobs up 5 meters up so the maximum height reached by him is -3.

( Since -8+5=-3)

So, the sine function that will represent this situation is:


f(x)=5\sin((\pi x)/(32))-8

Now, the graph of this situation is attached to the answer and the mid-line and the first and the second points on it are labelled.

PLEASE HELP WITH WHERE TO DOT!!! At an ocean depth of 8 meters, a buoy bobs up and-example-1
User Tim Klingeleers
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5.5k points