Question

The height, h, in feet of a gold ball above the ground after being hit into the air is given by the equation. H=-16t2+64t, where t is the number of seconds elapsed since the ball was hit. How many seconds does it take for the golf ball to hit the ground?

Answer 1

4 seconds

Explanation:

Given :
`H = -16t^(2) +64t`

To Find: How many seconds does it take for the golf ball to hit the ground?

Solution :

Since we are given an equation :
`H = -16t^(2) +64t`

Where H denotes height

t denotes the number of seconds elapsed since the ball was hit.

When he golf ball to hit the ground at that time the height becomes 0

So, put H = 0 in the equation

`H = - 16t^(2) +64t`

`0 = - 16t^(2) +64t`

`16t^(2) = 64t`

`16t = 64`

`t =(64)/(16)`

`t =4`

Thus it take 4 seconds for the golf ball to hit the ground