Question

John used linear combination to solve the system of equations shown. He did so by multiplying the first equation by -3 and the second equation by another number to eliminate the x-terms. What number did Jonas multiply the second equation by?

4x-6y=2

3x+5y=11

Answer 1

4

Explanation:

multiply the first equation by -3 would give you

-12x + 18y = -6

to eliminate x on the second equation, you would need 12x to cancel the -12x on the first equation

What number times 3x woud give you 12x? the answer would be 4.

lets multiply equation 2 by 4 to see what happens

12x + 20y = 44

So 12x will cancel -12x on the first equation

Good Luck!

Answer 2

John multiplied the second equation by 4.

Explanation:

We are given two linear equations and we know that John multiplied the first equation by -3 and the second equation by another number to eliminate the x-terms.

We are to find that another number.

4x-6y=2 --- (1)

3x+5y=11 --- (2)

Multiplying the first equation by -3 we get:

-12x + 18y = -6 --- (3)

Since we have to eliminate the x terms so coefficients of x must be the same with opposite signs. So we need 12x in the second equation to eliminate it.

For this, we need to multiply the second equation by 4 to get:

12x + 20y = 44