Question

player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. What is the horizontal velocity component of the ball to the nearest tenth of a m/s?

Answer 1

In this Question we have given,

Velocity, V=
`26(m)/(s)`

angle,α=30 degrees

We have to find horizontal component of velocity,

`V_(x)=V* Cos\alpha`

`V_(x)=26* Cos\30`

`V_(x)=26* 0.866`

`V_(x)=22.51(m)/(s)`

`V_(x)=23(m)/(s)`

Answer 2

22.5 m/s

Step-by-step explanation

We shall use the trigonometric ratio cosine to find the horizontal component.

cos = adjacent/hypotenuse

Adjacent is the horizontal and hypotenuse is the fly speed.

cos 30° = horizontal / 26

horizontal velocity = 26 × cos 30°

= 26 × 0.866

= 22.5166

= 22.5 m/s