177k views
2 votes
WORTH 100 POINTS need the answers asap

first row

-x^2
2x^2
(x/2)^2
x^2

x is less than 2
x is greater than 2
x is less than or equal to 2
x is greater than or equal to 2

second row

-5
-5/2
4
5

•2 is less than x&x is less than 4
•2 is less than or equal to x & x is less than or equal to 4
•2 is less than or equal to x&x is less than 4
•2 is less than x&x is less than or equal to 4

WORTH 100 POINTS need the answers asap first row -x^2 2x^2 (x/2)^2 x^2 x is less than-example-1
User Wige
by
7.8k points

2 Answers

3 votes
your sloping right? or n
User Eric Guo
by
7.6k points
3 votes

Answer:


f(x) = x^2 , x < 2


f(x) = 5, 2\leq x < 4

Explanation:

We are given a graph with a parabola and a line it it.

The parabola in the given graph goes until x = 2 but is not able to reach that very value. So x = 2 starts on the line above where x = 2 and ends just before the value of x = 4.

Therefore, this can be modeled by:


f(x) = x^2 , x < 2


f(x) = 5, 2\leq x < 4

User Msamedozmen
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories