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2 votes
WORTH 100 POINTS need the answers asap

first row

-x^2
2x^2
(x/2)^2
x^2

x is less than 2
x is greater than 2
x is less than or equal to 2
x is greater than or equal to 2

second row

-5
-5/2
4
5

•2 is less than x&x is less than 4
•2 is less than or equal to x & x is less than or equal to 4
•2 is less than or equal to x&x is less than 4
•2 is less than x&x is less than or equal to 4

WORTH 100 POINTS need the answers asap first row -x^2 2x^2 (x/2)^2 x^2 x is less than-example-1
User Wige
by
4.8k points

2 Answers

3 votes
your sloping right? or n
User Eric Guo
by
4.1k points
3 votes

Answer:


f(x) = x^2 , x < 2


f(x) = 5, 2\leq x < 4

Explanation:

We are given a graph with a parabola and a line it it.

The parabola in the given graph goes until x = 2 but is not able to reach that very value. So x = 2 starts on the line above where x = 2 and ends just before the value of x = 4.

Therefore, this can be modeled by:


f(x) = x^2 , x < 2


f(x) = 5, 2\leq x < 4

User Msamedozmen
by
4.1k points