What value is a discontinuity of x squared plus 8 x plus 4, all over x squared minus x minus 6?

Question

asked Nov 12, 2020 200k views

2 Answers

Shivaun · Answer 1 · 2020-11-18T12:19:59+0000

Answer:
$x=3\\x=-2$

Explanation:

1. You have the following expression:

(x^(2)+8x+4)/(x^(2)-x-6)

3. The denominatoir cannot be zero, so, you must find its roots:

x^(2)-x-6=0

Factorizing it, you obtain:

$(x-3)(x+2)=0\\x=3\\x=-2$

Then:

(x^(2)+8x+4)/((x-3)(x+2))

4. Therefore, the values that are discontinuity of
(x^(2)+8x+4)/(x^(2)-x-6) are:

$x=3\\x=-2$