Question

What value is a discontinuity of x squared plus 8 x plus 4, all over x squared minus x minus 6?

Answer 1

x=3

x=-2

Step-by-step explxanation:

Answer 2

Answer:
`x=3\\x=-2`

Explanation:

1. You have the following expression:

`(x^(2)+8x+4)/(x^(2)-x-6)`

3. The denominatoir cannot be zero, so, you must find its roots:

`x^(2)-x-6=0`

Factorizing it, you obtain:

`(x-3)(x+2)=0\\x=3\\x=-2`

Then:

`(x^(2)+8x+4)/((x-3)(x+2))`

4. Therefore, the values that are discontinuity of
`(x^(2)+8x+4)/(x^(2)-x-6)` are:

`x=3\\x=-2`