32.7k views
5 votes
Graph the equation.
y=4x^2+8x+7

Graph the equation. y=4x^2+8x+7-example-1

1 Answer

6 votes

Answer:

See attached graph.

Explanation:

To graph the quadratic, find the vertex using (-b/2a, f(-b/2a)).

The quadratic has values a=4, b =8, and c=7 from its standard form.

So -b/2a = -8/2(4) =-8/8 = -1.

f(-1) is 4(-1)^2 + 8(-1) + 7 = 4(1) -8+7 =4-8+7 = -4+7 = -3.

The vertex is the point (-1, -3).

To find another point, substitute x=0.

f(0) = 4(0)^2+8(0)+7 = 0+0+7 = 7.

Plot the point (0,7).

Graph the equation. y=4x^2+8x+7-example-1
User RobLabs
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories