159k views
1 vote
Fine the solution of 4x^2+4x+1=0

2 Answers

7 votes

Answer:

x = -
(1)/(2) with multiplicity 2

Explanation:

given 4x² + 4x + 1 = 0

This is a perfect square of the type

(a + b)² = a² + 2ab + b²

4x² = (2x)² ⇒ a = 2x, 1 = 1² ⇒ b = 1, and

2ab = 2 × 2x × 1 = 4x

4x² + 4x + 1 = 0

(2x + 1)² = 0, hence

x = -
(1)/(2) with multiplicity 2



User Pithhelmet
by
8.6k points
2 votes

Answer:

x = -1/2

Explanation:


User Pedro Lamas
by
8.7k points

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