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3 votes
What is the distance between (5 - 2i) and (8 + i)?

User Olvagor
by
6.8k points

2 Answers

5 votes

Answer:

3√2

Explanation:

We have to find distance between two points.

We represent a+bi as (a,b) on graph.

Hence, 5-2i can be represented as (5,-2).

and 8+i can be represented as (8,1).

By using distance formula, we can find distance between two points.

d=
\sqrt{(y_(2)-y_(1) )^(2) +(x_(2) -x_(1) )^(2)}

d=
\sqrt{(1-(-2))^(2)+(8-5)^(2)}

d=
\sqrt{(3)^(2) +(3)^(2) }

d=
√(9+9)

d=
√(18)

d=
√(9.2)

d=3√2 is distance between (5-2i) and (8+i).


User TomByrer
by
5.8k points
2 votes

Answer:


Explanation:

In complex plane we can see a+bi as the point (a,b).

so 5-2i can be seen as (5,-2)

and 8+i can be seen as (8,1)

Now we can use the distance formula to find the distance between the two points .

Distance formula is


D=√((x1-x2)^2+(y1-y2)^2)

Plugging the respective values we get


D= √(((5-8)^2+(-2-1)^2)\\D= \sqrt{(-3)^2+(-3)^2\\


D = √(9+9) \\D=√(18) \\D=3√(2)

so Distance is
3√(2)

User Zielony
by
6.5k points