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25 votes
Determine the vertex of the quadratic relation y=2(x+2)(x-6).

User Dbugger
by
7.7k points

2 Answers

8 votes

Answer:

vertex = (2, - 32 )

Explanation:

given a quadratic function in standard form

y = ax² + bx + c ( a ≠ 0 ) , then the x- coordinate of the vertex is

x = -
(b)/(2a)

given

y = 2(x + 2)(x - 6) ← expand factors using FOIL

= 2(x² - 4x - 12 ) ← distribute parenthesis

y = 2x² - 8x - 24 ← in standard form

with a = 2, b = - 8 , then

x = -
(-8)/(4) = 2

substitute x = 2 into the function for corresponding y- coordinate

y = 2(2 + 2)(2 - 6) = 2(4)(- 4) = 8 × - 4 = - 32

vertex = (2, - 32 )

User Lars De Bruijn
by
8.2k points
7 votes
The vertex is (2,-32)
User Erik Nijland
by
8.7k points

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