Question

You randomly draw a marble from a bag of marbles that contains 77 blue marbles, 22 green marbles, and 11 red marble.

What is \text{P(not draw a blue marble})P(not draw a blue marble)?

Answer 1

Answer:
`(3)/(10)`

Explanation:

Given: The number of blue marbles = 77

The total number of blue marbles =
`77+22+11=110`

Now, the probability of choosing a blue marble is given by :-

`\text{P( draw a blue)}=\frac{\text{Number of blue marbles}}{\text{ Total number of marbles}}\\\\\Rightarrow\ \text{P(draw a blue)}=(77)/(110)=(7)/(10)`

Now, the probability of not choosing a blue marble is given by :-

`\text{P(not draw a blue)}=1-\text{P( draw a blue)}\\\\\Rightarrow\ \text{P(not draw a blue)}= 1-(7)/(10)\\\\\Rightarrow\ \text{P(not draw a blue)}=(3)/(10)`

Answer 2

ANSWER


`P( \bar B)= (3)/(10)`

EXPLANATION

The number of blue marbles is

n(B)=77

The number of Green marbles is

n(G)=22

The number of red marbles is

n(R)=11

The total number of marbles is

n(S)=110


The probability of picking a blue marble is


`P(B)= (n(B))/(n(S))`




`P(B)= (77)/(110)`



`P(B)= (7)/(10)`


The probability of not selecting a blue marble is



`P( \bar B)= 1 - P(B).`




`P( \bar B)= 1 - (7)/(10)`



`P( \bar B)= (3)/(10)`