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Evaluate the limit as x approaches 1 of the ((square root of the quantity x squared plus 3 ) minus 2) all over x minus 1. Show work

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Answer:


\lim_(x \to 1)\frac{\sqrt{x^(2)+3 }-2}{{x-1}}=(1)/(2)

Explanation:


\lim_(x \to 1)\frac{\sqrt{x^(2)+3 }-2}{{x-1}}

if we put x = 1 directly in the epression above we will get an indeterminate form
(0)/(0), so instead we will use L’Hospital's Rule.


Take derivative of numerator and denominator separately and then apply the limit.



(d)/(d(x))\sqrt{x^(2)+3 }-2 = \frac{x}{\sqrt{x^(2)+3 } }\\(d)/(d(x)) (x-1) = 1\\


So now the expression becomes: By puttin x = 1 in the expression now we can find the solution


\lim_(x \to 1) \frac{\frac{x}{\sqrt{x^(2)+3 } }}{1}\\=\lim_(x \to 1)\frac{x}{\sqrt{x^(2)+3 }}\\=\frac{1}{\sqrt{1^(2)+3 }}\\=(1)/(√(1+3 ))\\=(1)/(√(4 ))\\=(1)/(2)


User PJ Fanning
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