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13 votes
13 votes
How many $4$-digit positive integers exist that satisfy the following conditions: (A) Each of the first two digits must be $1$, $4$, or $5$, and (B) the last two digits cannot be the same digit, and (C) each of the last two digits must be $5$, $7$, or $8$

User RobinL
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1 Answer

18 votes
18 votes

Answer:

54 possibles

Explanation:

Digit ONE 3 choices

Digit two 3 choices

digit three 3 choices

digit four 2 choices

3 x 3 x 3 x 2 = 54 choices meet all of the conditions

User Walino
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