Answer:
3. 6(2a +b) and 4. 2(6a + 3b)
Explanation:
To solve me must first look at the given expression:
Given that the 12 is being multiplied by the a and the 6 by the b, it make 12a and 6b two seperate terms:
- This means that you cannot add them together so 1 cannot be an option
Next, we can also eliminate 5 because you are not adding 12 and a or 6 and b, you are multiplying each respectively
We can also rule out 2 because you cannot get rid of variables, so therefore, a and b have to be in the given options
That leaves us with 3 and 4 as our only other options to choose from. To verify that these are valid equivalents we have to factor 12a + 6b:
You can take out a 2 from 12 and 6 → 2(6a + 3b)
You can also take out a 3, but the only option with that is one we eliminated
The only other number you can take out from each evenly is a 6 → 6(2a + b)
Therefore, 3 and 4 are your answers
I hope this helps!