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If seven consecutive numbers equal to 182, which one is the smallest?

User Bobby King
by
7.7k points

2 Answers

3 votes

Answer:

23.

Explanation:

My assumption: You mean when you add the numbers, they equal 182.

Let
x be the smallest number. Then we are asked to solve the following equation:


x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6) = 182.

Rearranging the equation gives us:

7x + 21 = 182 => x + 3 = 26 => x = 23.

So the smallest number is 23 (since our assumption was that x is the smallest number.

----

You could very well have stated that x was the middle number as a lot of cancellations would occur. That is:

(x - 3) + (x - 2) + (x - 1) + x + (x + 1) + (x + 2) + (x - 3) = 182.

7x = 182 => x = 26 so the smallest would be 26 - 3 = 23.

User Calvin Hu
by
7.9k points
1 vote

Answer:

the seven consecutive numbers would be 23 24 25 26 27 28 29

Explanation:


User Tonisuter
by
8.7k points

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