Answer:
x = -1±sqrt(5/3)
Explanation:
3x^2+6x=2
We will use completing the square
Factor out a 3 on the left
3(x^2 +2x) = 2
Divide each side by 3
3/3(x^2 +2x) = 2/3
(x^2 +2x) = 2/3
2/2 = 1 1^2 =1
Add 1 to each side
(x^2 +2x+1) = 2/3+1
(x+1) ^2 = 2/3 +3/3
(x+1)^2 = 5/3
Take the square root of each side
sqrt((x+1)^2) = ±sqrt(5/3)
x+1 = ±sqrt(5/3)
Subtract 1 from each side
x+1-1 = -1±sqrt(5/3)
x = -1±sqrt(5/3)