443,641 views
30 votes
30 votes
Multiply Conjugates Using the Product of Conjugates Pattern

In the following exercises, multiply each pair of conjugates using the Product of Conjugates Pattern
333. (4 − 6y)(4 + 6y)

User Charles Holbrow
by
2.6k points

1 Answer

28 votes
28 votes

Answer:

The product is the difference of squares is
$$\left(4-6y\right)\left(4+6y\right)=16-36{{y}^2}$$

Explanation:

Explanation

  • The given expression is (4-6 y)(4+6y).
  • We have to multiply the given expression.
  • Square the first term 4. Square the last term 6y.


$$\begin{aligned}&(4-6 y)(4+6 y)=(4)^(2)-(6 y)^(2) \\&(4-6 y)(4+6 y)=16-36 y^(2)\end{aligned}$$

User LaJmOn
by
2.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.