Answer:
The number of child tickets is 20 and the number of adult ticket is 18.
Explanation:
Let 'c' be the number of child tickets and 'a' be the number of adult tickets.
According to question,
Each child ticket for a ride costs $2.00, while each adult ticket costs $6.00
Total cost of child ticket = 2 × number of child rides
= 2c
Total cost of adult ticket = 6 × number of adult rides
= 6a
then, the ride collected a total of $148
This can be shown mathematically as,
2c + 6a = 148
Also given total 38 tickets were sold that is
c + a = 38
Thus, the system of equation becomes,
2c + 6a = 148 .........(1)
and c + a = 38 .......(2)
Solving system using Elimination method,
Multiply equation ( 2) by 6 , we get,
6c + 6a = 228 .........(3)
Now subtract (2) from (3), we get,
⇒ 6c + 6a -( 2c + 6a) = 228 - 148
⇒ 6c + 6a - 2c -6a = 228 - 148
⇒ 6c - 2c = 80
⇒ 4c = 80
⇒ c = 20
Substitute c = 20 in (2) , to solve for a , we get
c + a = 38 ⇒ 20 + a = 38 ⇒ a = 38 -20 ⇒ a = 18
Thus, the number of child tickets is 20 and the number of adult ticket is 18.