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A volleyball player hit a ball with a mass of 0.25 kg. The average acceleration of the ball is 15.5 m/s². How much force did the volleyball player apply to the ball? 62.0 N 3.87 N 62.0 m/s² 3.87 m/s²

2 Answers

6 votes

F=MA

0.25Kg.15.5M/S^2

= 3.875N


4 votes

This should be in the Physics section...

The formula which links mass, acceleration and force is:


F = ma

So to calculate the force applied, we can substitute the values from the question into the formula:


F = 0.25 * 15.5 = 3.875 N

Thus, the answer is 3.875 N

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