What is the following equation formed when completing the square on Y^2-12y=-27

Question

asked May 22, 2020 194k views

2 Answers

James Sapam · Answer 1 · 2020-05-29T15:22:44+0000

Answer:

(y -6)^(2) = 9

Explanation:

Given the function:

y^(2) -12y = -27

To find the completing the square of the above function, we use the following formula:

a^2-2ab+b^2=(a-b)^2. So we have:

y^(2) -12y = -27

$y^2-2* x* 6+6^2=-27+6^2\\(y-6)^2=-27+36\\ (y-6)^2=9.$

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