Question

What is the following equation formed when completing the square on Y^2-12y=-27

Answer 1

Answer:y^1=3 ,y^2=9 if im wrong sorry im wrong but hope you get an a

Answer 2

`(y -6)^(2) = 9`

Explanation:

Given the function:

`y^(2) -12y = -27`

To find the completing the square of the above function, we use the following formula:

`a^2-2ab+b^2=(a-b)^2.` So we have:

`y^(2) -12y = -27`

`y^2-2* x* 6+6^2=-27+6^2\\(y-6)^2=-27+36\\ (y-6)^2=9.`

Hope it can find you well.