Question

A church luncheon made $842. Adult tickets cost $10 each and children's tickets cost $6 each. The number of children was 12 more than twice the number of Adults. how many of each ticket were sold?

Answer 1

42 adults and 96 children

Explanation:

42x + 96c = 842

x=10

c=6

Answer 2

adult tickets 35 and children's ticket 82

Explanation:

Given: A church luncheon made
`\$842`. Adult tickets cost
`\$10` each and children's tickets cost
`\$6` each. The number of children was
`12` more than twice the number of Adults.

To Find: how many of each ticket were sold.

Solution:

Let the number of adults be
`=\text{a}`

Let the number of children be
`=\text{c}`

cost of adult ticket
`=\$10`

cost of children ticket
`=\$6`

Total value of tickets sold
`=\$842`

Now,

total sale of ticket

`=10\text{a}+6\text{c}`

as given

`\text{c}=2\text{a}+12`

putting in equation

`842=6(12+2\text{a})+10\text{a}`

`842=22\text{a}+72`

`770=22\text{a}`

`\text{a}=35`

now,

`\text{c}=2\text{a}+12`

`\text{c}=2*35+12`

`\text{c}=82`

Hence number of adult tickets are
`35` and number of children's ticket are
`82`.