Answer:
Choice D is correct answer.
Step-by-step explanation:
Given equation is :
6x²-2x+3= 0
ax²+bx+c =0 is general quadratic equation.
x = (-b±√b²-4ac) / 2a is quadratic formula to find the solution of quadratic equation.
Comparing general equation with quadratic equation, we get
a = 6 ,b = -2 and c = 3
putting above values in quadratic formula, we get
x = (-(-2)±√(-2)²-4(6)(3)) / 2(6)
x = (2±√4-72) / 12
x = ( 2±√-68) / 12
Since, √-68 is complex number which is in the solution of given equation.
Hence, given equation has no real solution.