Question

If 15 drops of ethanol from a medicine dropper weigh 0.60g, how many drops does it takes from a dropper to dispense 1.0ml of ethanol? Density of ethanol is ethanol is 0.80g/ml.

Answer 1

It takes approximately 9.6 drops from a dropper to dispense 1.0 mL of ethanol.

Step-by-step explanation:

To determine how many drops it takes to dispense 1.0 mL of ethanol, we can use the given information about the density of ethanol and the mass of 15 drops of ethanol. First, we can calculate the mass of 1.0 mL of ethanol:

Mass = Density x Volume

Mass = 0.80 g/mL x 1.0 mL = 0.80 g

Next, we can set up a proportion to find the number of drops:

(Mass of 15 drops) / (Number of drops) = (Mass of 1.0 mL) / (1.0 mL)

0.60 g / 15 drops = 0.80 g / Number of drops

Cross-multiply and solve for Number of drops:

Number of drops = (0.60 g x Number of drops) / 15 drops x 0.80 g

Number of drops = 9.6 drops

Therefore, it takes approximately 9.6 drops from a dropper to dispense 1.0 mL of ethanol.

Answer 2

20.0 drops.

Step-by-step explanation:

• Firstly, we need to know the volume of the 15 drops that weigh 0.60 g.

• We can get the volume from the relation: d = m / V.

Where, d is the density (d = 0.80 g/ml),

m is the mass (m = 0.60 g),

V is the volume (??? ml)

∴ V = m / d = (0.60 g) / (0.80 g/ml) = 0.75 ml.

Using cross multiplication:

15.0 drops will dispense → 0.75 ml of ethanol.

??? drops will dispense → 1.0 ml of ethanol.

∴ The number of drops that will dispense 1.0 ml of ethanol = (1.0 ml) (15.0 drops) / (0.75 ml) = 20.0 drops.