Question

Find the equation of the axis of symmetry for the parabola y=x^2-6x+41/5

Answer 1

x = 3

Explanation:

given a parabola in standard form : y = ax² + bx + c : a ≠ 0

Then the equation of the axis of symmetry is

x = -
`(b)/(2a)`

y = x² - 6x +
`(41)/(5)` is in standard form

with a = 1 and b = - 6, hence

x = -
`(-6)/(2)` = 3

equation of axis of symmetry is x = 3