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At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed students at West Junior High are proportional to the numbers at East Middle School.

User Joel Lord
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2 Answers

5 votes

Answer:

38

Explanation:

Lets say, first number = x


Second number = 3x+7


Total = 49



(x)+(3x+7)= 49


4x+7 = 49


4x = 42


x = 42/4


x= 10.5



x= 10.5


3x+7 = 3(10.5)+7 = 38



Hope this helps!!

User Robin B
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8.6k points
4 votes

Answer: Hello there!

in East middle school there are 58 left-handed students and 609 right-handed students.

You could calculate the ratio between them in the next way:

divide the biggest number by the smaller one:

x = 609/58 = 10.5.

then the proportion is 1:10.5 wich means that for every left-handed student, you have 10.5 right-handed students, but the 10.5 looks weird, we could write this ratio as 2:21 by multiplying each side by 2.

and now for every two lefthanded students, there are 21 right-handed students:

now you know that at West Junior High the proportion between left-handed students and right-handed students is proportional to the numbers at East Middle School.

this means that the ratios are equivalent, or:

if there are Y left-handed students at West Junior High, then there are X = 10.5*Y right-handed students in West Junior High.

Where X and Y are not necessarily equal than in East Middle School, just the ratios are proportional between them

User Desmondhume
by
8.9k points
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