Question

Triangle TUV is graphed on the coordinate plane below.

The figure is rotated 270°counterclockwise using the origin as the center of rotation. Where is point V’?
(1, –3)
(3, –1)
(–3, 1)
(–1, 3)

Answer 1

The correct option is 2.

Explanation:

If a figure rotated 270°counterclockwise with origin as the center of rotation, then

`(x,y)\rightarrow (y,-x)`

From the given graph it is clear that the coordinates of V are (1,3), the coordinates of V' are

`V(1,3)\rightarrow V'(3,-1)`

The coordinates of V' are (3,-1).

Therefore the correct option is 2.

Answer 2

Answer: point V' is located at (3,-1)