Question

Find the value of r so that the line through (-4,3) and (r,-3) has a slope of 2/3.

If solved is it possible for you to write out what you did.

Answer 1

r = -13

Explanation:

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have the slope m = 2/3 and the points (-4, 3) and (r, -3). Substitute:

`(-3-3)/(r-(-4))=(2)/(3)`

`(-6)/(r+4)=(2)/(3)` cross multiply

`2(r+4)=(-6)(3)` divdide both sides by 2

`r+4=(-3)(3)`

`r+4=-9` subtract 4 from both sides

`\boxed{r=-13}`