Answer:
0.32
Explanation:
We have been given that at a high school, the probability that a student is a senior is 0.25. The probability that a student plays a sport is 0.20. The probability that a student is a senior and plays a sport is 0.08.
We will use conditional probability formula to solve our given problem.
, where,
= The probability of event B given event A.
= The probability of event A and event B.
=Probability of event A.
Let A be that the student is senior and B be the student plays a sport.
P(A and B) = Probability that student is a senior and plays a sport.
![P(B|A)=\frac{\text{Probability that a student is a senior and plays a sport}}{\text{Probability that a student is senior}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/p3pm07rsikszd95nt7lfg8ebxa0jf9z9o9.png)
Upon substituting our given values we will get,
![P(B|A)=(0.08)/(0.25)](https://img.qammunity.org/2020/formulas/mathematics/high-school/udkzdfc1adf0yhznfqjrupqe5v78sn7tjj.png)
![P(B|A)=0.32](https://img.qammunity.org/2020/formulas/mathematics/high-school/ct6wnkayp4wcw5schqrih9mxpacdh9yx8h.png)
Therefore, the probability that a randomly selected student plays a sport, given that the student is a senior will be 0.32.