Question

Suppose that one of millikan's oil drops has a charge of −4.8×10−19

c. how many excess electrons does the drop contain?.

Answer 1

The best and correct option is c

Answer 2

Answer: The number of excess electrons that the drop contains are 3.

Step-by-step explanation:

We are given:

Charge on millikan's oil drops =
`4.8* 10^(-19)C`

To calculate the number of excess electrons, we divide the charge on millikan's oil drop by the change on 1 electron.

`\text{Excess electrons}=\frac{\text{Charge on millikan's oil drop}}{\text{Charge on 1 electron}}`

We know that:

Charge on 1 electron =
`1.60* 10^(-19)C`

Putting values in above equation, we get:

`\text{Excess electrons}=(4.8* 10^(-19)C)/(1.60* 10^(-19)C)\\\\\text{Excess electrons}=3`

Hence, the number of excess electrons that the drop contains are 3.