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MATH: FINDING HALF LIFE PT 1

MATH: FINDING HALF LIFE PT 1-example-1
User Eskimwier
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1 Answer

9 votes

Answer:

15.4 years

Explanation:

An investment is doubled when it is twice its initial value. The equation can be solved for the value of t that makes this true.

Setup

In the exponential equation for investment value, the factor y₀ is the initial value of the investment. We want to find t when y = 2y₀.

2y₀ = y₀·e^(0.045t)

Solution

Dividing by y₀ gives ...

2 = e^(0.045t)

Taking natural logarithms, we have ...

ln(2) = 0.045t

Dividing by the coefficient of t gives its value:

t = ln(2)/0.045 ≈ 15.4

The investment will be doubled after 15.4 years.

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Additional comment

The continuously compounded interest rate for this investment is 4.5%. The doubling time is 0.693 divided by this: 0.693/0.045 ≈ 15.4. This relationship holds for any sort of continuous compounding.

User Shravan Dhar
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