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What is the range of the function y =^3 Square root x+ 8?

2 Answers

4 votes

Answer:

all real numbers

Explanation:

The range of any odd root function is all real numbers, cube root included.

y = ∛(x+8)

is defined for all values of x. It may take on any value for y.

____

The horizontal scale of the graph is quite large so as to show the vertical extent keeps increasing. (The x-intercept is -8.)

What is the range of the function y =^3 Square root x+ 8?-example-1
User Jtruelove
by
5.4k points
7 votes

Answer:

The range of the function is: -∞≤y≤∞.

Explanation:

Consider the provided function


y=\sqrt[3]{x+8}

The range of the function is the set of all values which a function can produce or the set of y values which a function can produce after substitute the possible values of x.

The range of a cubic root function is all real numbers.

Now consider the provided function.


y=\sqrt[3]{x+8}

The above function can be written as:


y=(x+8)^{(1)/(3)}

Taking cube on both sides.


y^3=x+8\\\\x=y^3-8

The graph of the function is shown in figure 1:

For any value of x we can find different value of y.

Here, the cube root function can process negative values. Since, the function can produce any values, the range of the given function is -∞≤y≤∞ .

Therefore, the range of the function is: -∞≤y≤∞.

What is the range of the function y =^3 Square root x+ 8?-example-1
User Benjamin Schulte
by
5.3k points