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Which point corresponds to the real zero of the graph of y = log2 (x + 2) - 1?

1 Answer

2 votes

Answer:

(0, 0)

Explanation:

Ok so you have the equation:
y = log_2{(x+2)}-1. To find the zero you simply set the y equal to zero and then solve for x


0 = log_2{(x+2)}-1

Add 1 to both sides


1 = log_2{x+2}

Rewrite the equation in exponential form:


2^1=x+2

Subtract 2 from both sides


0 = x

So the zero of the function is at the origin (0, 0)

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