Question

Which point corresponds to the real zero of the graph of y = log2 (x + 2) - 1?

Answer 1

(0, 0)

Explanation:

Ok so you have the equation:
`y = log_2{(x+2)}-1`. To find the zero you simply set the y equal to zero and then solve for x

`0 = log_2{(x+2)}-1`

Add 1 to both sides

`1 = log_2{x+2}`

Rewrite the equation in exponential form:

`2^1=x+2`

Subtract 2 from both sides

`0 = x`

So the zero of the function is at the origin (0, 0)