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Solve 14x2 + 42x + 70 = 0.

A) 1 plus or minus i square root 11
B) the quantity of negative 3 plus or minus i square root 29 all over 2
C) the quantity of negative 3 plus or minus 2i square root 29 all over 2
D) the quantity of negative 3 plus or minus i square root 11 all over 2

2 Answers

5 votes

Answer:

d

Explanation:

User Evan Carslake
by
7.9k points
4 votes

Answer:


x = -(3)/(2) + (√(11))/(2)i or
x = -(3)/(2) - (√(11))/(2)i

Explanation:


14x^2 + 42x + 70 = 0

First, divide both sides by 14.


x^2 + 3x + 5 = 0

There are no two real numbers whose product is 5 and whose sum is 3, so this polynomial is not factorable. We use the quadratic formula.


x = (-b \pm √(b^2 - 4ac))/(2a)

We have a = 1; b = 3; c = 5.


x = (-3 \pm √((-3)^2 - 4(1)(5)))/(2(1))


x = (-3 \pm √(9 - 20))/(2)


x = (-3 \pm √(-11))/(2)


x = (-3 \pm i√(11))/(2)


x = -(3)/(2) + (√(11))/(2)i or
x = -(3)/(2) - (√(11))/(2)i

User Aleksandr Zolotov
by
7.9k points

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