Question

Solve x2 + 6x + 4 = 0.

a) x equals the quantity of negative 6 plus or minus square root 24 all over 2
b) x equals negative 3 plus or minus square root 5
c) x equals the quantity of negative 6 plus or minus square root 54 all over 2
d) x equals 3 plus or minus 2 square root 5

Answer 1

Option b)
`x=(-3\pm √(5))`.

Explanation:

We have to solve the equation x²+6x+4 =0 for the value of x.

As we know from any quadratic equation ax²+bx+c=0

the value of
`x=\frac{-b\pm \sqrt{b^(2)-4ac}}{2a}`

Now with the help of this formula we will solve the equation

x²+6x+4 = 0

By putting the values of a= 1, b=6, c=4 in the formula

`x=\frac{-6\pm \sqrt{6^(2)-4* 1* 4}}{2* 1}`

`x=(-6\pm √(36-16))/(2)`

`x=(-6\pm √(20))/(2)`

`x=(-6\pm √(4* 5))/(2)`

`x=(-6\pm 2√(5))/(2)`

`x=(2(-3\pm √(5)))/(2)`

`x=-3\pm √(5)`

so the final answer is
`x=(-3\pm √(5))`