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What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)?

y – 1=(x + 3)
y – 1=(x + 3)
y – 1= (x + 3)
y – 1= (x + 3)

What is the equation, in point-slope form, of the line that is parallel to the given-example-1

2 Answers

2 votes

Answer: y - 1= 3/2 (x + 3)


Explanation:


User Awais Jameel
by
8.3k points
3 votes

Answer:

The required equation is
y-1=(3)/(2)(x+3)

Explanation:

The equation of given line is


y-2=(2+4)/(2+2)(x-2)


y-2=(3)/(2)(x-2)


y=(3)/(2)x-1

The slope of the given equation is
(3)/(2)

As we know the slope of parallel line is equal.

Thus, The slope of required line is
(3)/(2)

Passing point: (-3,1)

Using point slope formula:


y-y_1=m(x-x_1)


y-1=(3)/(2)(x+3)

Hence, The required equation is
y-1=(3)/(2)(x+3)

User Alec Holmes
by
8.0k points

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