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What are the zeros of the function f(x) = x^2+4x+3?

x = 4, x = 3
x = -1, x = 3
x = -1, x = -3
x = 1, x = 3

2 Answers

3 votes

Answer:

x=-1,x=-3

Explanation:


x^(2)+4x+3\\x^(2) +3x+x+3\\x(x+3)+1(x+3)\\(x+3)(x+1)\\

Therefore zeros of the function will be;


x+3=0,x+1=0\\x=-3,x=-1

User Jseabold
by
8.5k points
6 votes

Answer:

Option (3) is correct.

The zero of given function
f(x)=x^2+4x+3 is x= -1 and x= -3.

Explanation:

Consider the given function
f(x)=x^2+4x+3

We need to find the zero of the above function. Put f(x)=0

then ,
f(x)=x^2+4x+3=0 \Rightarrow x^2+4x+3=0

The above function represents a quadratic equation

We can solve the quadratic equation by splitting middle term method,


\Rightarrow x^2+4x+3=0

We can write 4x as x+ 3x ,


\Rightarrow x^2+x+3x+3=0


\Rightarrow x(x+1)+3(x+1)=0


\Rightarrow (x+1)(x+3)=0


\Rightarrow (x+1)=0 or
\Rightarrow (x+3)=0


\Rightarrow x=-1 or
\Rightarrow x=-3

Thus, the zero of given function
f(x)=x^2+4x+3 is x= -1 and x= -3.

User Unutbu
by
8.4k points

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