Question

What are the zeros of the function f(x) = x^2+4x+3?

x = 4, x = 3
x = -1, x = 3
x = -1, x = -3
x = 1, x = 3

Answer 1

x=-1,x=-3

Explanation:

`x^(2)+4x+3\\x^(2) +3x+x+3\\x(x+3)+1(x+3)\\(x+3)(x+1)\\`

Therefore zeros of the function will be;

`x+3=0,x+1=0\\x=-3,x=-1`

Answer 2

Option (3) is correct.

The zero of given function
`f(x)=x^2+4x+3` is x= -1 and x= -3.

Explanation:

Consider the given function
`f(x)=x^2+4x+3`

We need to find the zero of the above function. Put f(x)=0

then ,
`f(x)=x^2+4x+3=0 \Rightarrow x^2+4x+3=0`

The above function represents a quadratic equation

We can solve the quadratic equation by splitting middle term method,

`\Rightarrow x^2+4x+3=0`

We can write 4x as x+ 3x ,

`\Rightarrow x^2+x+3x+3=0`

`\Rightarrow x(x+1)+3(x+1)=0`

`\Rightarrow (x+1)(x+3)=0`

`\Rightarrow (x+1)=0` or
`\Rightarrow (x+3)=0`

`\Rightarrow x=-1` or
`\Rightarrow x=-3`

Thus, the zero of given function
`f(x)=x^2+4x+3` is x= -1 and x= -3.