Question

How many solutions doe

Answer 1

Option D is correct, i.e. two solutions.

Explanation:

Given the equation is 6x² + 40 = -31x.

Rearranging the terms:- 6x² +31x +40 = 0.

Then a = 6, b = 31, c = 40.

Finding Discriminant as follows:-

D = b² -4ac

D = 31² -4*6*40

D = 961 - 960

D = 1

If we have positive value of D, then it has two real solutions.

Hence, option D is correct, i.e. two solutions.

Answer 2

Given equation have two solutions.

x =
`-(5)/(2) and -(8)/(3)`

Right option is (D)

Explanation:

We have given,

`6x^(2) +40=-31x`

we can rewrite this equation in the form given as:

6x² + 40 + 31x = 0

or 6x² + 31x + 40 = 0

On solving this quadratic equation, we get :

x =
`-(5)/(2) and -(8)/(3)`

That means, given equation have two solutions.

Right option is (D)