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Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2).

The equation of this circle is (x + )2 + (y + )2 =

User Pimentel
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1 Answer

11 votes

Answer:


(x-5)^2+(y+4)^2=100

Explanation:

Equation of a circle


(x-a)^2+(y-b)^2=r^2

where:

  • (a, b) is the center
  • r is the radius

Given:

  • center = (5, -4)
  • point on circle = (-3, 2)

Substitute the given values into the circle equation and solve for r:


\implies r^2=(-3-5)^2+(2-(-4))^2


\implies r^2=(-8)^2+(6)^2


\implies r^2=64+36


\implies r^2=100


\implies r=√(100)


\implies r=10

Substitute the given center and the found value of r into the circle equation to create the equation of the circle:


\implies (x-5)^2+(y-(-4))^2=10^2


\implies (x-5)^2+(y+4)^2=100

User Mirageglobe
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