A rhombus has sides 10 cm long and an angle of 30°. Find the distance between a pair of opposite sides.

Question

asked May 7, 2020 110k views

2 Answers

VincentZHANG · Answer 1 · 2020-05-14T09:09:25+0000

Answer:

The perpendicular distance between the opposite sides of rhombus is 5 units.

Explanation:

Given a rhombus has sides 10 cm long and an angle of 30°.

we have to find the distance between opposite two sides of rhombus.

Since side of rhombus is 10 cm and one of the acute angle is of 30° then

In ΔAED,

$sin\angle DAE=(DE)/(AD)$

⇒
$sin30^(\circ)=(DE)/(10)$

⇒
DE=(1)/(2)* 10=5

Hence, the perpendicular distance between the opposite sides of rhombus is 5 cm