Question

A rhombus has sides 10 cm long and an angle of 30°. Find the distance between a pair of opposite sides.

Answer 1

5 cm

Explanation:

Answer 2

The perpendicular distance between the opposite sides of rhombus is 5 units.

Explanation:

Given a rhombus has sides 10 cm long and an angle of 30°.

we have to find the distance between opposite two sides of rhombus.

Since side of rhombus is 10 cm and one of the acute angle is of 30° then

In ΔAED,

`sin\angle DAE=(DE)/(AD)`

⇒
`sin30^(\circ)=(DE)/(10)`

⇒
`DE=(1)/(2)* 10=5`

Hence, the perpendicular distance between the opposite sides of rhombus is 5 cm