Answer:
Probability of choosing a heart and rolling a 2 =
![(1)/(24)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2ejqnssmykp357mksu6sz08xx1wxgsbb.png)
Explanation:
Let A be the event of choosing a heart from a standard deck of cards and
B be the event of rolling a 2.
Clearly, A and B are independent events as none of the events does not affect the probability of occurrence of other event.
Therefore, P(A∩B) = P(A) × P(B)
P(A) =
![(Number of heart cards)/(Total number of cards)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9gzj78vsn4z519okrob2s6gkkxffc22hpg.png)
![=(13)/(52)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8pp0zuk29c1oilumooazh1q0t8nkhlnma4.png)
![=(1)/(4)](https://img.qammunity.org/2020/formulas/mathematics/college/tv4zmuyd6232lkgdxqbx85ic9a23udqtvt.png)
P(B) =
![(1)/(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1hfsyqujpiw8kz1nwo0zeow75fj0n2oyv6.png)
P(A∩B) = P(A) × P(B)
=
![(1)/(4) ((1)/(6) )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/816y78cwkpzjdplj52plry24zktk8nym44.png)
![=(1)/(24)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v6hk0i1oofwxf4wjiulao2ioey7eso8dn9.png)