Question

There are three consecutive even integers. If twice the first integer added to the second is 268,244, find all three integers.

Answer 1

89414,89416,89418

Explanation:

Let n bet the positive integer and then 2n is an even integer because multiplying n with 2 makes it an even integer.

Now, 2n+2, 2n+4 are the next integers.

Therefore, three consecutive integers are: 2n, 2n+2, 2n+4.

It is given that twice the first integer added to the second is 268,244 that means:

`2(2n)+(2n+2)=268244`

`4n+2n+2=268244`

`6n=268242`

`n=44707`

Therefore, three consecutive integers are:

2n=89414, 2n+2=89416, 2n+4=89418