Question

A basketball player passes the ball to a teammate. The ball reaches a velocity of 5.5 m/s, 2 seconds after the ball leaves the player’s hands. What is the acceleration of the ball during those two seconds?

Answer 1

acceleration = 2.25 m/s²

Step-by-step explanation:

`a = (v - u)/(t)`

where:

a = acceleration (?)

v = final velocity (5.5 m/s)

u = initial velocity (0 m/s, because the ball starts from rest)

t = time taken (2s).

Using the formula:

acceleration =
`(5.5 - 0 )/(2)`

= 2.75 m/s²