Answer:
The most money he can borrow : $ 17916.67
Explanation:
Formula for Monthly Payment is given by :
![P=(r* PV)/(1-(1+r)^(-n))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x8i9e6yjgmazawhzv9fd6xnec750ypzswx.png)
P : Monthly Payment = $1290
r : Rate per period = 7.2%
n : Number of periods = 360
To be calculated : PV : Present Value
Now, Substituting values in the formula :
![1290=((7.2)/(100)* PV)/(1-(1+(7.2)/(100))^(-360))\\\\PV=(1290* (1-(1.072)^(-360)))/(0.072)\\\\\bf\implies PV=\$17916.67](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ylx6jy1cndi3zgay0h6pos5fb9huvulm8s.png)
So, the most money he can borrow : $ 17916.67