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Im confused on how to do this

Im confused on how to do this-example-1

1 Answer

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Explanation :

(1) No. of jumping jacks,
n=120

time,
t=6\ minutes=360\ sec

So, frequency is
f=(n)/(t)


f=(120)/(360\ sec)


f=0.33 Hz

(2) The quarter spins 10 times every seconds

So, frequency
f=10\ Hz

and the period of one cycle is,
t=(1)/(10\ Hz)


t=0.1\ sec

(3) mass of block,
m=1.3\ Kg

force constant of spring,
K=250\ N/m

Time period of oscillations is given by :


T=2\pi \sqrt{(m)/(k)}


T=2\pi \sqrt{(1.3\ Kg)/(250\ N/m)}

So,
T=0.45\ sec

Frequency,
F=(1)/(time\ period)


F=(1)/(0.45\ sec)


F=2.22\ Hz

User Nwe
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