Question

Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires solving for x, and the known values for the system are a=2.55meter/second2, v0=21.8meter/second, and v=0meter/second. Perform the next step in the analysis.

Answer 1

To solve for x in the equation v^2 = v0^2 + 2ax, substitute the known values for v0, v, and a. Given a = 2.55 m/s^2, v0 = 21.8 m/s, and v = 0 m/s, the calculated value for x is approximately -191.76 meters.

Step-by-step explanation:

To solve for x in the equation v^2 = v0^2 + 2ax, we can substitute the known values for v0, v, and a.

Given that a = 2.55 m/s², v0 = 21.8 m/s, and v = 0 m/s, we can plug these values into the equation:

v^2 = v0^2 + 2ax

(0 m/s)^2 = (21.8 m/s)^2 + 2(2.55 m/s²)x

Simplifying the equation, we get:

0 = 21.8^2 + 5.1x

Now, we can solve for x by isolating the variable:

5.1x = -21.8^2

x = -21.8^2 / 5.1

Calculating this expression gives the value of x as approximately -191.76 meters.

Answer 2

As per kinematics equation we are given that

`v^2 = v_o^2 + 2ax`

now we are given that

a = 2.55 m/s^2

`v_0 = 21.8 m/s`

`v = 0`

now we need to find x

from above equation we have

`0^2 = 21.8^2 + 2(2.55)x`

`0 = 475.24 + 5.1 x`

`x = 93.2 m`

so it will cover a distance of 93.2 m